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1890 Belgian general election
First party
Second party
Leader
Auguste Beernaert
Party
Catholic
Liberal
Leader's seat
Candidate for PM
Seats before
98 seats
40 seats
Seats won
29
40
Seats after
94
44
Seat change
4
4
Popular vote
17,253
20,829
Percentage
45.15%
54.51%
Partial general elections were held in Belgium on 10 June 1890.[1] [2] In the elections for the Chamber of Representatives the result was a victory for the Catholic Party , which won 94 of the 138 seats.[2]
Under the alternating system, elections were held in only four out of the nine provinces: Hainaut , Limburg , Liège and East Flanders . Thus, only 69 seats out of the 138 were up for election. Additionally, a special election was held in Neufchâteau on 3 June 1890.[3]
Results [ edit ]
Chamber of Representatives [ edit ]
Party Votes % Seats Won Total +/– Liberal Party 20,829 54.51 40 44 +4 Catholic Party 17,253 45.15 29 94 –4 Belgian Labour Party 98 0.26 0 0 New Others 30 0.08 0 0 0 Total 38,210 100.00 69 138 0 Total votes 38,210 – Registered voters/turnout 59,452 64.27 Source: Mackie & Rose,[4] Sternberger et al .
Constituencies [ edit ]
The distribution of seats among the electoral districts was as follows:[5]
References [ edit ]