Talk:Distonic ion

Page contents not supported in other languages.
From Wikipedia, the free encyclopedia

Untitled[edit]

Overall, the article is easy to read and understand and a good brief introduction to the topic. It will be accessible to a wide range of readers.

It will benefit from additional secondary sources, for anyone interested doing further research about the subject.

Also, the coverage is limited at this time. For example, a brief discussion of the different techniques for detecting presence of distonic ions would be beneficial to the overall article. Remilawal (talk) 22:12, 10 April 2019 (UTC)[reply]

Kayla Richardson 11.4.2019 . 2:24 PM Okay i will work on expanding this information with more images and additional secondary sources immediately to upgrade the quality i will expand on the experiments used to detect their presence and the different classes the distonic ions are able to fall into thank you for the feedback

Wiki Education Foundation-supported course assignment[edit]

This article was the subject of a Wiki Education Foundation-supported course assignment, between 9 January 2019 and 26 April 2019. Further details are available on the course page. Student editor(s): Mailangrichardson. Peer reviewers: Remilawal.

Above undated message substituted from Template:Dashboard.wikiedu.org assignment by PrimeBOT (talk) 11:01, 18 January 2022 (UTC)[reply]

Distonic ion needs to be doubly charged or not?[edit]

First of all, thank you to anyone writing or editing this article. I am confused about the first sentence in the definition:

'Distonic ions are chemical species that contain two ionic charges on the same molecule, ...'

You mention thus that the ion needs to be doubly charged (a radical site does not make a molecule charged). However, you later on show many examples of singly-charged molecules and a radical site. Is this a wrong formulation in the first sentence, or do I misunderstand something?

Best regards, Bart — Preceding unsigned comment added by 131.169.66.206 (talk) 10:06, 5 May 2022 (UTC)[reply]