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Election in Rhode Island
1836 United States presidential election in Rhode Island
County Results
Van Buren
50-60%
Harrison
50-60%
The 1836 United States presidential election in Rhode Island took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election . Voters chose four representatives, or electors to the Electoral College , who voted for President and Vice President .
Rhode Island voted for Democratic candidate Martin Van Buren over Whig candidate William Henry Harrison . Van Buren won Rhode Island by a narrow margin of 4.48%.
This was the first time that Rhode Island ever voted for a Democratic presidential candidate, and Van Buren's performance would not be bettered by a Democrat in Rhode Island until Franklin D. Roosevelt in 1932 .[1]
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