User talk:Clive tooth

Welcome![edit]

Hello, Clive tooth, and welcome to Wikipedia! Thank you for your contributions. I hope you like the place and decide to stay. Here are a few links to pages you might find helpful:

Please remember to sign your messages on talk pages by typing four tildes (~~~~); this will automatically insert your username and the date. If you need help, check out Wikipedia:Questions, ask me on my talk page, or ask your question on this page and then place {{help me}} before the question. Again, welcome! RJFJR (talk) 14:02, 19 July 2013 (UTC)[reply]

Just made another modification to the final entry at Timeline of the far future[edit]

Is my math up to snuff? :) Serendi ^pod ous 12:57, 13 April 2016 (UTC)[reply]

Yes, your maths is fine. 10^10^10^56 is such a vast number that just multiplying it by any number smaller than it leaves it pretty much the same. In fact we can go much, much further...

Let us give 10^10^10^56 the name K. As far as the "Timeline of the far future" is concerned, the next "number of interest" after K is, I suppose, 10^10^10^57.

As you probably know 10^100 is usually called a googol. What happens when we raise K to the power of a googol? That is, what is K×K×K×K× ... ×K where there are a googol Ks?

Let's see...

Let A = K^googol = K^(10^100) = (10^10^10^56)^(10^100) = 10^((10^100)×(10^10^56) = 10^10^(100+10^56)

That is, the 10^56 in the definition of K has (for A) been increased by just 100, to 10^56 + 100. Still an enormous way from our next "number of interest" 10^10^10^57.

In other words

K = 10^10^100000000000000000000000000000000000000000000000000000000 [a 1 followed by 56 zeros]

And K^googol = 10^10^100000000000000000000000000000000000000000000000000000100 [where the 54th zero has become a 1]

So K^googol = K, as far as we are concerned. :) --Clive tooth (talk) 17:28, 13 April 2016 (UTC)[reply]