Talk:Loschmidt constant/Derivation

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The following is a slightly modified version of Loschmidt's derivation of the relationship between molecular diameter and macroscopic properties.

We start from Maxwell's equation for the mean free path of gas molecules of diameter d when the number density of molecules (the number of molecules per unit volume) is n0:

Next we rearrange this to find the quantity 1/n0. As n0 is the number of molecules per unit volume, 1/n0 is the volume per "unit molecule" in the gas phase.

At this point, Loschmidt makes a slight digression, but we need simply to say that "true volume" of a spherical molecule of diameter d (and hence radius r) is given by simple geometry. Nowadays, this quantity is known as the van der Waals volume, so we shall denote it Vvdw

Loschmidt's genius was to realize that he could estimate Vvdw from the macroscopic properties of liquids and gases, notably their densities. Let us take Vgas as the volume occupied by a molecule in the gas phase, that is 1/n0, and Vliq as the volume occupied by a molecule in the liquid phase. Obviously, VliqVgas, as liquids are much denser than gases. For N molecules, each of mass m, the densities are defined as:

,

Hence

However, there is still a small amount of free space between the molecules in a liquid. The closest that spherical molecules can approach one another is by close-packing of spheres, as might be expected in a solid (and is found in many solids, although Loschmidt could only surmise this). In a close-packed arrangement the spheres only occupy 74% of the volume: This figure is now known as the atomic packing factor, so we shall denote it as φAPF: for a regular arrangement of spheres, it can be calculated by geometry (although Loschmidt's geometry seems to have failed him here, as he used an incorrect value for close-packing). Loschmidt realized that the atomic packing factor φAPF for a liquid must be only slightly lower than φAPF for a solid, because liquids are only slightly less dense than solids. By estimating φAPF,liq, he could state

and

By substituting the definitions of Vvdw (= πd3/6) and Vgas (= 1/n0), we obtain

Substituting the unknown number density n0 by its definition in terms of the (measurable) mean free path:

gives

which trivially rearranges to Loschmidt's result.